which function has an asymptote at x=pi/2?a) y= sec xb) y= cot xc) y= csc xd) y= cos x
Accepted Solution
A:
Answer:Step-by-step explanation:Note that y= sec x is the same as y = 1 / cos x, and that cos x is 0 at π/2. Division by zero is not defined. Thus, x cannot = π/2, and there is a vertical asymptote there.Thus, the first answer choice, y = sec x, is the correct one.