What are the dimensions of the lightest open-top right circular cylindrical can that will hold a volume of 2744 cmcubed3?
Accepted Solution
A:
Answer: r=2.808cm h = 100cm then we get volume of cylinder that is 2744 As explained belowStep-by-step explanation:Volume of cylinder = πr²hSurface area of cylinder = 2πrh +πr² (1) h= 2744 /πr²put value oh h in equation (1)Area =[2πr] 2744 /πr² =[5488/r +πr²]dA/dx=0 i.e 2πr=5488/r²Solving this r.r= ∛5488/2π =2.808taking second derivation we get 100