The width of a rectangle is 19 meters more than the length. The perimeter is 242 meters. Find the length and width.

Answer:The length of the rectangle is 51 meters and the width is 70 meters.Step-by-step explanation:Let us assume that the length of the rectangle is L and the width of the same rectangle is W. it is given in the problem that, the width of the rectangle is 19 meters more than the length. Hence, L+19 =W ......(1) Again, the perimeter of the rectangle is given by 2(L+W), which is given to be 242 meters. So, 2(L+W) =242, ⇒L+W =121 ..... (2) Now, solving equations (1) and (2) by substitution method, we get, L+(L+19) =121, ⇒2L =102, ⇒ L =51 meters. Now, from equation (1), W=L+19 =70 meters. Therefore, the length of the rectangle is 51 meters and the width is 70 meters. (Answer)